InOutArgument<T>.FromExpression Method
Definition
Important
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Initializes and returns a new InOutArgument<T> constructed using the specified Activity<TResult>.
public:
static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)Parameters
Returns
The new argument.
Applies to
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