Edit

Share via

Control.Hyperlink property (Access)

  • Article

Use the Hyperlink property to return a reference to a Hyperlink object and to access the properties and methods of a control's hyperlink. Read-only.

Syntax

expression.Hyperlink

expression A variable that represents a Control object.

Example

The CreateHyperlink procedure in the following example sets the hyperlink properties for a command button, label, or image control to the address and subaddress values passed to the procedure. The address setting is an optional argument, because a hyperlink to an object in the current database uses only the subaddress setting.

To try this example, create a form with two text box controls (txtAddress and txtSubAddress) and a command button (cmdFollowLink), and paste the following into the Declarations section of the form's module.

Private Sub cmdFollowLink_Click() 
 CreateHyperlink Me!cmdFollowLink, Me!txtSubAddress, _ 
 Me!txtAddress 
End Sub 
 
Sub CreateHyperlink(ctlSelected As Control, _ 
 strSubAddress As String, Optional strAddress As String) 
 Dim hlk As Hyperlink 
 Select Case ctlSelected.ControlType 
 Case acLabel, acImage, acCommandButton 
 Set hlk = ctlSelected.Hyperlink 
 With hlk 
 If Not IsMissing(strAddress) Then 
 .Address = strAddress 
 Else 
 .Address = "" 
 End If 
 .SubAddress = strSubAddress 
 .Follow 
 .Address = "" 
 .SubAddress = "" 
 End With 
 Case Else 
 MsgBox "The control '" & ctlSelected.Name _ 
 & "' does not support hyperlinks." 
 End Select 
End Sub

Support and feedback

Have questions or feedback about Office VBA or this documentation? Please see Office VBA support and feedback for guidance about the ways you can receive support and provide feedback.