numeric_limits::denorm_min
Returns the smallest nonzero denormalized value.
static Type denorm_min( ) throw( );
Return Value
The smallest nonzero denormalized value.
Remarks
long double is the same as double for the C++ compiler.
The function returns the minimum value for the type, which is the same as min if has_denorm is not equal to denorm_present.
Example
// numeric_limits_denorm_min.cpp
// compile with: /EHsc
#include <iostream>
#include <limits>
using namespace std;
int main( )
{
cout << "The smallest nonzero denormalized value\n for float "
<< "objects is: " << numeric_limits<float>::denorm_min( )
<< endl;
cout << "The smallest nonzero denormalized value\n for double "
<< "objects is: " << numeric_limits<double>::denorm_min( )
<< endl;
cout << "The smallest nonzero denormalized value\n for long double "
<< "objects is: " << numeric_limits<long double>::denorm_min( )
<< endl;
// A smaller value will round to zero
cout << numeric_limits<float>::denorm_min( )/2 <<endl;
cout << numeric_limits<double>::denorm_min( )/2 <<endl;
cout << numeric_limits<long double>::denorm_min( )/2 <<endl;
}
The smallest nonzero denormalized value for float objects is: 1.4013e-045 The smallest nonzero denormalized value for double objects is: 4.94066e-324 The smallest nonzero denormalized value for long double objects is: 4.94066e-324 0 0 0
Requirements
Header: <limits>
Namespace: std