PropertyBuilder<TProperty>.HasPrecision Method
Definition
Important
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Overloads
| HasPrecision(Int32) |
Configures the precision of the property. |
| HasPrecision(Int32, Int32) |
Configures the precision and scale of the property. |
HasPrecision(Int32)
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
Configures the precision of the property.
public virtual Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<TProperty> HasPrecision (int precision);override this.HasPrecision : int -> Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<'Property>Public Overridable Function HasPrecision (precision As Integer) As PropertyBuilder(Of TProperty)Parameters
- precision
- Int32
The precision of the property.
Returns
The same builder instance so that multiple configuration calls can be chained.
Applies to
HasPrecision(Int32, Int32)
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
- Source:
- PropertyBuilder%60.cs
Configures the precision and scale of the property.
public virtual Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<TProperty> HasPrecision (int precision, int scale);override this.HasPrecision : int * int -> Microsoft.EntityFrameworkCore.Metadata.Builders.PropertyBuilder<'Property>Public Overridable Function HasPrecision (precision As Integer, scale As Integer) As PropertyBuilder(Of TProperty)Parameters
- precision
- Int32
The precision of the property.
- scale
- Int32
The scale of the property.
Returns
The same builder instance so that multiple configuration calls can be chained.
Applies to
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Entity Framework